Blind 75 - Top K Frequent Elements - IMP

Learning From

Asked at

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Source

Video

https://youtu.be/7KHKFqLPMbs

Problem and Constraints

Get k numbers repeated most often.

All Approaches and Explanations in English

O(n*log n)

count all numbers. sort. and return top k. Use streams to make it cleaner.

Code, if any

Normal Solution

class Solution {
    private int[] bruteforce(int[] nums, int k) {
        Map<Integer, Integer> counts = new HashMap<>();
        for(int num: nums){ // O(n)
            counts.put(num, counts.getOrDefault(num, 0) + 1);
        }
        return counts.entrySet()
                .stream()
                .sorted(Map.Entry.comparingByValue()) // // O(n * log(n))
                .skip(counts.size() - k)
                .map(Map.Entry::getKey)
                .mapToInt(Integer::intValue)
                .toArray();
    }
    public int[] topKFrequent(int[] nums, int k) {
        return bruteforce(nums, k);
    }
}